# Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set: 16

$y=-4x+4$

#### Work Step by Step

The given line has a slope of -4 and goes through the point (2,-4). We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=-4$ and $(x_{1},y_{1})=(2,-4)$. $y+4=-4(x-2)=-4x+8$ Subtract 4 from both sides. $y=-4x+4$ This line is now in the slope-intercept form of $y=mx+b$.

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