## Intermediate Algebra (6th Edition)

$y=-2x-1$
The given line has a slope of -2 and goes through the point (1,-3). We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=-2$ and $(x_{1},y_{1})=(1,-3)$. $y+3=-2(x-1)=-2x+2$ Subtract 3 from both sides. $y=-2x-1$ This line is now in the slope-intercept form of $y=mx+b$.