#### Answer

$y=4x+21$

#### Work Step by Step

The given line has a slope of 4 and goes through the point (5,1).
We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=4$ and $(x_{1},y_{1})=(5,1)$.
$y-1=4(x-5)=4x-20$
Add 1 to both sides.
$y=4x+21$
This line is now in the slope-intercept form of $y=mx+b$.