Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.4 - The Slope of a Line - Exercise Set - Page 164: 101

Answer

L1 = $-2$ L2 = $-1$ L3 = -$\frac{2}{3}$

Work Step by Step

Since slope is $\frac{rise}{run}$, we can find slope by doing $\frac{y2-y1}{x2-x1}$. The two given points for L1 are (-1, 4) and (2, -2). If we plug these points into the formula, we get $\frac{-2 -4}{2--1}$. This simplifies to $\frac{-6}{3}$, or $-2$. The two given points for L2 are (-8, 6) and (-4, 2). If we plug these points into the formula, we get $\frac{2-6}{-4--8}$. This simplifies to $\frac{-4}{4}$, or -1. The two given points for L3 are (-6, 0) and (0, -4). If we plug these points into the formula, we get $\frac{-4-0}{0--6}$. This simplifies to $\frac{-4}{6}$, or -$\frac{2}{3}$.
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