## Intermediate Algebra (6th Edition)

The slope of the line is 0 and the y-intercept is (0,$-\frac{11}{2}$).
We are given that $2y+4=-7$. We can transform this line into the slope-intercept form $y=mx+b$, where m is the slope of the line and the point (0,b) is the y-intercept. First, subtract 4 from both sides. $2y=-11$ Divide both sides by 2. $y=-\frac{11}{2}=0x-\frac{11}{2}$ $m=0$ and $b=-\frac{11}{2}$ Therefore, the slope of the line is 0 and the y-intercept is (0,$-\frac{11}{2}$).