## Intermediate Algebra (6th Edition)

The slope of this line is $m=-\frac{3}{4}$ and the y-intercept is (0,-$\frac{3}{2}$).
We are given that $-3x-4y=6$. We can transform this equation into the slope-intercept form y=mx+b, where m is the slope, and the point (0,b) is the y-intercept of the line. First, add -3x to both sides. $-4y=3x+6$ Divide both sides by -4. $y=-\frac{3}{4}x-\frac{6}{4}=-\frac{3}{4}x-\frac{3}{2}$ $m=-\frac{3}{4}$ and $b=-\frac{3}{2}$ Therefore, the slope of this line is $m=-\frac{3}{4}$ and the y-intercept is (0,-$\frac{3}{2}$).