Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.2 - Introduction to Functions - Exercise Set - Page 143: 115

Answer

$a. 0$ $b. 3a - 12$ $c. -3x - 12$ $d. 3x + 3h - 12$

Work Step by Step

$f(x) = 3x - 12$ $a.$ $f(4)$ $f(4) = 3(4) - 12$ $f(4) = 12 - 12$ $f(4) = 0$ $b.$ $f(a)$ $f(a) = 3(a) - 12$ $f(a) = 3a - 12$ $c. f(-x)$ $f(-x) = 3(-x) - 12$ $f(-x) = -3x - 12$ $d. f(x + h)$ $f(x + h) = 3(x + h) - 12$ $f(x + h) = 3x + 3h - 12$
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