Intermediate Algebra (6th Edition)

Published by Pearson

Chapter 3 - Section 3.2 - Introduction to Functions - Exercise Set: 64b

Answer

$-\frac{1}{9}$

Work Step by Step

We are given that $h(x)=-x^{2}$. $h(-\frac{1}{3})=-(-\frac{1}{3})^{2}=-(-\frac{1}{3}\times-\frac{1}{3})=-(\frac{1}{9})=-\frac{1}{9}$

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