Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.2 - Introduction to Functions - Exercise Set - Page 141: 62b

Answer

$\frac{1}{3}$

Work Step by Step

We are given that $g(x)=-\frac{1}{3}x$ $g(-1)=-\frac{1}{3}\times-1=\frac{1}{3}$
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