Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.2 - Introduction to Functions - Exercise Set: 58

Answer

1

Work Step by Step

We are given that $g(x)=4x^{2}-6x+3$. $g(1)=4\times1^{2}-6\times1+3$ $4\times1\times1-6\times1+3=4-6+3=1$
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