## Intermediate Algebra (6th Edition)

$(-∞,-4]$
We are given that $9x+8\leq6x-4$. In order to solve for x, first subtract 6x from both sides. $3x+8\leq-4$ Subtract 8 from both sides. $3x\leq-12$ Divide both sides by 3. $x\leq-4$ Therefore, the solution set consists of all values of x that are less than or equal to -4.