Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.1 - Graphing Equations - Exercise Set: 52

Answer

See graph
1485016581

Work Step by Step

$y=\frac{1}{2}x-3$ This is a linear equation. Substitute values for x to find their corresponding y-values. $y=\frac{1}{2}(0)-3$ $y=-3$ $(0,-3)$ $y=\frac{1}{2}(2)-3$ $y=-2$ $(2,-2)$ $y=\frac{1}{2}(-2)-3$ $y=-4$ $(-2,-4)$ Plot these points and connect with a straightedge.
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