Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.1 - Graphing Equations - Exercise Set - Page 126: 51

Answer

See graph

Work Step by Step

$y=\frac{1}{3}x-1$ This is a linear equation. Substitute values for x to find their corresponding y-values. $y=\frac{1}{3}(0)-1$ $y=-1$ $(0,-1)$ $y=\frac{1}{3}(3)-1$ $y=0$ $(3,0)$ $y=\frac{1}{3}(-3)-1$ $(-3,-2)$ Plot these points and connect with a straightedge.
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