Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.1 - Graphing Equations - Exercise Set - Page 126: 45

Answer

See graph

Work Step by Step

$y=|x+2|$ This is not a linear equation. Substitute values for x to find their corresponding y-values. $y=|0+2|$ $y=2$ $(0,2)$ $y=|-1+2|$ $y=1$ $y=|-2+2|$ $y=0$ $(-2,0)$ $y=|-3+2|$ $y=1$ Plot these points and connect with a straightedge.
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