Answer
Both are solutions
Work Step by Step
We are given that $y=x^{4}$.
In order to see whether each ordered pair is a solution of the given equation, we can plug in the ordered pair to the equation.
For (-1,1): $(-1)^{4}=-1\times-1\times-1\times-1=1$
So, (-1,1) is a solution.
For (2,16): $2^{4}=2\times2\times2\times2=16$
So, (2,16) is a solution.