Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Review - Page 197: 111

Answer

Please see the graph.

Work Step by Step

Red line: $y\gt 2x+3$ Blue line: $x\le-3$ Let's use the point $(0,0)$ to determine what sides of the lines to shade. Red line: $y\gt 2x+3$ $y\gt 2x+3$ $0 \gt 2*0+3$ $0 \gt 0+3$ $0 \gt 3$ (false) We'll shade the side of the red line that doesn't have $(0,0)$ on that side. We have a "greater than" sign, so we'll use a dotted line. Blue line: $x\le-3$ $x \le -3$ $0 \le -3$ (false) We'll shade the side of the blue line that doesn't have $(0,0)$ on that side. We have a "less than or equal to" sign, so we'll use a solid line. The union of the two areas is the area that is shaded blue and red.
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