Answer
neither
Work Step by Step
Using $y=mx+b$, where $m$ is the slope, the slope of $
f(x)=-2x+6
$ is
\begin{array}{l}
m_1=-2
\end{array}
and the slope of $g(x)=2x-1$ is
\begin{array}{l}
m_2=2
.\end{array}
Since $m_1\ne m_2$ and $m_1\cdot m_2\ne-1,$ then the given lines are $\text{
neither parallel nor perpendicular
.}$