Answer
see graph
Work Step by Step
Changing the given inequality, $
2x-y\lt6
,$ to equality and then isolating $y$ result to
\begin{array}{l}\require{cancel}
2x-y=6
\\\\
-y=-2x+6
\\\\
y=2x-6
.\end{array}
Use the table of values below to graph this line.
Since the inequality used is "$
\\lt
$", use a broken line.
Using the test point $(
0,0
)$, then
\begin{array}{l}\require{cancel}
2(0)-0\lt6
\\\\
0\lt6
\text{ (TRUE)}
.\end{array}
Since the solution above ended with a $\text{
TRUE
}$ statement, then the test point is $\text{
part
}$ of the solution set.