## Intermediate Algebra (6th Edition)

$y=\frac{1}{4}x-3$
We are given that the y-intercept of the line is $(0,-3)$ and the slope is $\frac{1}{4}$. Since we know the slope and y-intercept of the line, we can write the equation in slope intercept form, $y=mx+b$ (where m is the slope of the line and b is the y-coordinate of the y-intercept). Therefore, $y=\frac{1}{4}x+(-3)=\frac{1}{4}x-3$.