## Intermediate Algebra (6th Edition)

$\frac{2}{3}\lt\frac{3}{4}$
$\frac{2}{3}=\frac{2}{3}\times\frac{4}{4}=\frac{8}{12}$ $\frac{3}{4}=\frac{3}{4}\times\frac{3}{3}=\frac{9}{12}$ $\frac{8}{12}$ is to the left of $\frac{9}{12}$ on the number line. Therefore, $\frac{2}{3}$ is less than $\frac{3}{4}$ in value.