Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Cumulative Review: 7b

Answer

$\frac{1}{16}$

Work Step by Step

$(\frac{1}{2})^{4}=(\frac{1}{2})\times(\frac{1}{2})\times(\frac{1}{2})\times(\frac{1}{2})=\frac{1\times1\times1\times1}{2\times2\times2\times2}=\frac{1}{16}$
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