## Intermediate Algebra (6th Edition)

$(0,-12)$ and $(2,-6)$ are solutions.
To determine whether or not each ordered pair is a solution of the equation, we can plug each into the equation. For $(0,-12)$: $3\times0-(-12)=12$. This is true, so $(0,-12)$ is a solution. For $(1,9)$: $3\times1-(9)=-6\ne12$. So, $(1,9)$ is not a solution. For $(2,-6)$: $3\times2-(-6)=12$. So, $(2,-6)$ is a solution.