## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 3 - Cumulative Review: 38

#### Answer

$(-∞,-4)U(-2,∞)$

#### Work Step by Step

We are given that $|x+3|\gt1$. Therefore, $x+3\gt1$ or $x+3\lt-1$. We can solve both of these inequalities to find solutions. For $x+3\gt1$, subtract 3 from both sides. $x\gt-2$ For $x+3\lt-1$, subtract 3 from both sides. $x\lt-4$ Therefore, the solution set consists of all values of x that are less than -4 or greater than -2.

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