Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Cumulative Review - Page 199: 30

Answer

All real numbers

Work Step by Step

We are given that $x-2\lt6$ or $3x+1\gt1$. Therefore, a solution only needs to satisfy one of the inequalities. We can first solve $x-2\lt6$ for x. Add 2 to both sides. $x\lt8$ Next, can first solve $3x+1\gt1$ for x. Subtract 1 from both sides. $3x\gt0$ Divide both sides by 3. $x\gt0$ Therefore, the solution set consists of all numbers that are either greater than 0 or less than 8, which includes all real numbers.
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