## Intermediate Algebra (6th Edition)

We are given that $2x\geq0$ and $4x-1\leq-9$. Therefore, any solution for x must satisfy both inequalities. We can first solve $2x\geq0$ for x. Divide both sides by 2. $x\geq0$ Next, we can solve $4x-1\leq-9$ for x. Add 1 to both sides. $4x\leq-8$ Divide both sides by 4. $x\leq-2$ Therefore, the solution set is empty because no real number can be greater than or equal to 0 and also less than or equal to -2.