## Intermediate Algebra (6th Edition)

An odd integer has a value of exactly 2 less than its next consecutive odd integer. And each following consecutive odd integer will be exactly 2 more in value than the previous odd integer. The sum of 3 consecutive odd integers: $x+(x+2)+(x+2+2)=(x+x+x)+(2+2+2)=3x+6$ We can set this sum equal to 213. $3x+6=213$ Subtract 6 from both sides. $3x=207$ Divide both sides by 3. $x=69$ Number 1: 69 Number 2: 69+2=71 Number 3: 69+2+2=73