Intermediate Algebra (6th Edition)

An even integer has a value of exactly 2 less than its next consecutive even integer. And each following consecutive even integer will be exactly 2 more in value than the previous even integer. The sum of 3 consecutive even integers: $x+(x+2)+(x+2+2)=(x+x+x)+(2+2+2)=3x+6$ We can set this sum equal to 264. $3x+6=264$ Subtract 6 from both sides. $3x=258$ Divide both sides by 3. $x=86$ Number 1: 86 Number 2: 86+2=88 Number 3: 86+2+2=90