Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Test - Page 114: 21

Answer

$\text{the interval } \left[ 1,\dfrac{11}{2} \right) $

Work Step by Step

Using the properties of inequality, the solution to the given inequality, $ -1 \le \dfrac{2x-5}{3} \lt 2 ,$ is \begin{array}{l}\require{cancel} -1\cdot3 \le \dfrac{2x-5}{3}\cdot3 \lt 2\cdot3 \\\\ -3 \le 2x-5 \lt 6 \\\\ -3+5 \le 2x-5+5 \lt 6+5 \\\\ 2 \le 2x \lt 11 \\\\ \dfrac{2}{2} \le \dfrac{2}{2}x \lt \dfrac{11}{2} \\\\ 1 \le x \lt \dfrac{11}{2} .\end{array} In interval notation, the solution is $ \text{the interval } \left[ 1,\dfrac{11}{2} \right) .$
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