Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Test: 6

Answer

$\frac{29}{4}$.

Work Step by Step

Solve the equation: $\frac{z+7}{9}$+1=$\frac{2z+1}{6}$. $\frac{z+7}{9}$+1=$\frac{2z+1}{6}$ Multiply both sides by 18. 2(z+7)+18=3(2z+1) Distribute the 2 and the 3. 2z+14+18=6z+3 Combine like terms. 2z+32=6z+3 Subtract 6z from both sides. -4z+32=3 Subtract 32 from both sides. -4z=-29 Divide. z=$\frac{29}{4}$
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