Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Test: 15

Answer

x$\le-\frac{11}{3}$.

Work Step by Step

Solve the inequality: $\frac{3x-2}{3}-\frac{5x+1}{4}\ge$0. Multiply both sides by 12. 12($\frac{3x-2}{3})-12(\frac{5x+1}{4})\ge$0(12) Reduce. 4($\frac{3x-2}{3})-3(\frac{5x+1}{4})\ge$0 Distribute. 12x-8-15x-3$\ge$0 -3x-11$\ge$0 -3x$\ge$11 Divide. remember to flip the greater than to a less than symbol. $\frac{-3x}{-3}\le{11}{-3}$ x$\le-\frac{11}{3}$.
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