Answer
x$\le-\frac{11}{3}$.
Work Step by Step
Solve the inequality: $\frac{3x-2}{3}-\frac{5x+1}{4}\ge$0.
Multiply both sides by 12.
12($\frac{3x-2}{3})-12(\frac{5x+1}{4})\ge$0(12)
Reduce.
4($\frac{3x-2}{3})-3(\frac{5x+1}{4})\ge$0
Distribute.
12x-8-15x-3$\ge$0
-3x-11$\ge$0
-3x$\ge$11
Divide. remember to flip the greater than to a less than symbol.
$\frac{-3x}{-3}\le{11}{-3}$
x$\le-\frac{11}{3}$.