Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.7 - Absolute Value Inequalities - Vocabulary, Readiness & Video Check - Page 105: 2

Answer

Choice E

Work Step by Step

Since $|x|\le c$ implies $-c\le x\le c,$ then the the given inequality, $ |2x+1|\le3 ,$ is equivalent to \begin{array}{l}\require{cancel} -3\le 2x+1\le3 .\end{array} Hence, $\text{ Choice E .}$
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