Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.7 - Absolute Value Inequalities - Exercise Set - Page 106: 96

Answer

$|x|>1$

Work Step by Step

Since for any $a\gt0$, $|x|\gt a$ implies $x\gt a$ OR $x\lt -a$, then the given inequality, $ x\gt1 \text{ or } x\lt-1 ,$ is equivalent to \begin{array}{l}\require{cancel} |x|>1 .\end{array}
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