Answer
$|x|>1$
Work Step by Step
Since for any $a\gt0$, $|x|\gt a$ implies $x\gt a$ OR $x\lt -a$, then the given inequality, $
x\gt1 \text{ or } x\lt-1
,$ is equivalent to
\begin{array}{l}\require{cancel}
|x|>1
.\end{array}
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