Answer
$P(\text{rolling a }1,2,3,4,5\text{ or } 6)=1$
Work Step by Step
Rolling a 1, 2, 3, 4, 5, or 6 is all the possible outcomes of rolling a die. Hence the probability of rolling a 1, 2, 3, 4, 5, or 6 is
\begin{array}{l}\require{cancel}
P(\text{rolling a }1,2,3,4,5\text{ or } 6)=\dfrac{6}{6}
\\\\
P(\text{rolling a }1,2,3,4,5\text{ or } 6)=1
.\end{array}