Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.7 - Absolute Value Inequalities - Exercise Set: 65

Answer

$(-2,5)$

Work Step by Step

$|2x-3| \lt 7$ This is equivalent to $-7 \lt 2x-3 \lt 7$ Using inequality properties, add $3 $ to all three parts. $-7+3 \lt 2x-3+3 \lt 7+3$ $-4 \lt 2x \lt 10$ Divide all parts by $2 $ $\frac{-4}{2} \lt \frac{2x}{2} \lt \frac{10}{2}$ $-2 \lt x \lt 5$ In Interval Notation: $(-2,5)$
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