Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.7 - Absolute Value Inequalities - Exercise Set - Page 106: 55

Answer

$x=\dfrac{3}{8}$

Work Step by Step

The left side of the given expression, $ \left| \dfrac{8x-3}{4} \right|\le0 ,$ always gives a non-negative value. Hence, the solution set to the given inequality is \begin{array}{l}\require{cancel} \dfrac{8x-3}{4}=0 \\\\ 8x-3=0(4) \\\\ 8x-3=0 \\\\ 8x=3 \\\\ x=\dfrac{3}{8} .\end{array}
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