Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.7 - Absolute Value Inequalities - Exercise Set - Page 106: 37

Answer

no solution

Work Step by Step

Using the properties of inequality, the given expression, $ 5+|x|\le2 ,$ is equivalent to \begin{array}{l}\require{cancel} |x|\le2-5 \\\\ |x|\le-3 .\end{array} The left side of the inequality above always gives a non-negative value. This will never be less than the negative value at the right. Hence, there is $\text{ no solution .}$
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