## Intermediate Algebra (6th Edition)

Original Equation |$\frac{n}{3}$+2|=4 Take $\frac{n}{3}$+2 and solve $\frac{n}{3}$+2=4 Multiply both sides by 3 n+6=12 Subtract 6 from both sides n=6 Make $\frac{n}{3}$+2 negative and solve -$\frac{n}{3}$-2=4 Multiply both sides by -3 n+6=-12 Subtract 6 from both sides n=-18