Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set: 7

Answer

x=4 x=8

Work Step by Step

Original Equation |$\frac{x}{2}$-3|=1 Take $\frac{x}{2}$-3 and solve $\frac{x}{2}$-3=1 Multiply both sides by 2 x-6=2 Add 6 to both sides x=8 Make $\frac{x}{2}$-3 negative and solve -$\frac{x}{2}$+3=1 Multiply both sides by -2 x-6=-2 x=4
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