## Intermediate Algebra (6th Edition)

Solutions are $8,-7$
$|\frac{2x-1}{3}| = |-5|$ $|-5| = 5$, we can write it as $|\frac{2x-1}{3}| = 5$ This statement is equivalent to $\frac{2x-1}{3} = 5$ or $\frac{2x-1}{3} = -5$ $2x-1 = 15$ or $2x-1 = -15$ $2x = 15+1$ or $2x= -15+1$ $2x = 16$ or $2x= -14$ $x = 8$ or $x= -7$ Solutions are $8,-7$