Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set: 59

Answer

Solutions are $8,-7$

Work Step by Step

$|\frac{2x-1}{3}| = |-5|$ $|-5| = 5 $, we can write it as $|\frac{2x-1}{3}| = 5$ This statement is equivalent to $\frac{2x-1}{3} = 5$ or $\frac{2x-1}{3} = -5$ $2x-1 = 15$ or $2x-1 = -15$ $2x = 15+1 $ or $2x= -15+1$ $2x = 16 $ or $2x= -14$ $x = 8 $ or $x= -7$ Solutions are $8,-7$
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