Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Exercise Set: 55

Answer

Solutions are $13,-8$

Work Step by Step

$|\frac{2x-5}{3}| = 7$ We can write it as $\frac{2x-5}{3}= 7$ or $\frac{2x-5}{3} = -7$ $2x-5 = 21$ or $2x-5 = -21$ $2x = 21 +5 $ or $2x = -21+5$ $2x = 26 $ or $2x=-16$ $x= 13 $ or $x=-8$ Solutions are $13,-8$.
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