## Intermediate Algebra (6th Edition)

c=$\frac{3}{2}$ c=$\frac{7}{6}$
Original Equation |8-6c|=1 Take 8-6c and solve 8-6c=1 Subtract 8 from both sides -6c=-7 Divide both sides by -6 c=$\frac{7}{6}$ Make 8-6c negative and solve -8+6c=1 Add 8 to both sides 6c=9 Divide both sides by 6 c=$\frac{3}{2}$