## Intermediate Algebra (6th Edition)

y=-$\frac{2}{3}$
Original Equation |3y+2|=0 Take 3y+2 and solve 3y+2=0 Subtract 2 from both sides 3y=-2 Divide both sides by 3 y=-$\frac{2}{3}$ Make 3y+2 negative and solve -3y-2=0 Add 2 to both sides -3y=2 Divide both sides by -3 y=-$\frac{2}{3}$