Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.4 - Linear Inequalities and Problem Solving - Exercise Set - Page 86: 59

Answer

$($-$\infty$, -$\frac{11}{2}$$]$

Work Step by Step

$\frac{2}{5}x$ - $\frac{1}{4}$ $\leq$ $\frac{3}{10}x$ - $\frac{4}{5}$ $\frac{2}{2}$( $\frac{2}{5}x$ ) - $\frac{5}{5}$( $\frac{1}{4}$ ) $\leq$ $\frac{3}{10}x$ - $\frac{4}{4}$( $\frac{4}{5}$ ) $\frac{4}{10}x$ - $\frac{5}{20}$ $\leq$ $\frac{3}{10}x$ - $\frac{16}{20}$ $\frac{1}{10}x$ $\leq$ -$\frac{11}{20}$ $20$( $\frac{1}{10}x$ ) $\leq$ $20$( -$\frac{11}{20}$ ) $2x$ $\leq$ $-11$ $x$ $\leq$ -$\frac{11}{2}$ In interval notation, the solution set is $($-$\infty$, -$\frac{11}{2}$$]$
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