## Intermediate Algebra (6th Edition)

$(\frac{14}{3}, ∞)$
$-6x+2 \lt -3(x+4)$ Using Distributive property, $-6x+2 \lt -3x-12$ Add $12$ on both sides. $-6x+2+12 \lt -3x-12+12$ $-6x+14 \lt -3x$ Add $6x$ on both sides. $-6x+14+6x \lt -3x+6x$ $14\lt 3x$ Divide by $3$ on both sides. $\frac{14}{3} \lt x$ is same as $x \gt \frac{14}{3}$ Interval Notation : $(\frac{14}{3}, ∞)$