Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.4 - Linear Inequalities and Problem Solving - Exercise Set: 44

Answer

$(\frac{14}{3}, ∞)$

Work Step by Step

$-6x+2 \lt -3(x+4)$ Using Distributive property, $-6x+2 \lt -3x-12$ Add $12$ on both sides. $-6x+2+12 \lt -3x-12+12$ $-6x+14 \lt -3x$ Add $6x$ on both sides. $-6x+14+6x \lt -3x+6x$ $14\lt 3x$ Divide by $3$ on both sides. $\frac{14}{3} \lt x$ is same as $ x \gt \frac{14}{3}$ Interval Notation : $(\frac{14}{3}, ∞)$
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