Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.4 - Linear Inequalities and Problem Solving - Exercise Set: 30

Answer

[$\frac{8}{3}$, infinity)

Work Step by Step

Original equation 5(x+4)$\leq$4(2x+3) Distribute 5x+20$\leq$8x+12 Subtract 8x and 20 from both sides -3x$\leq$-8 DIvide both sides by -3 x$\geq$$\frac{8}{3}$ Convert to interval notation [$\frac{8}{3}$, infinity)
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