Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.4 - Linear Inequalities and Problem Solving - Exercise Set - Page 85: 24

Answer

$[-3,\infty)$

Work Step by Step

$8-5x\leq23$ Solve for x by subtracting 8 from each side then multiplying each side by -5. When multiplying by a negative number you must reverse the inequality sign $8-5x-8\leq23-8$ $-5x\leq15$ $-5x\div-5\geq15\div-5$ $x\geq-3$ This is expressed in interval notation as $[-3,\infty)$ where [ indicates that -3 is included in the solution set for x.
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