Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.3 - Formulas and Problem Solving - Exercise Set - Page 75: 44b

Answer

$v=16.76 mm^3$

Work Step by Step

$v=\frac{4}{3}\pi r^2$ $v=\frac{4}{3}\pi (2)^2$ $v=16.76 mm^3$
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