Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set: 94

Answer

$x=4$

Work Step by Step

We are given that $x(x+1)+16=x(x+5)$. We can use the distributive property to simplify both sides. $x\times(x+1)+16=x\times(x+5)$ $x^{2}+x+16=x^{2}+5x$ Subtract $x^{2}$ from both sides. $x+16=5x$ Subtract x from both sides. $16=4x$ Divide both sides by 4. $x=4$
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