## Intermediate Algebra (6th Edition)

$K=-23$
We are given the equation $\frac{7}{11}x+9=\frac{3}{11}x-14$ and the equation $\frac{7}{11}x=\frac{3}{11}x+K$ In order to find the value of K that makes both equations equivalent, we must move all constant terms in the first equation to the right side. For $\frac{7}{11}x+9=\frac{3}{11}x-14$, subtract 9 from both sides. $\frac{7}{11}x=\frac{3}{11}x-5$. Therefore, both equations will be equivalent when $K=-23$.