## Intermediate Algebra (6th Edition)

$x=\frac{2}{3}$
$-3(x-4)=10$ $-3x+12=10$ $(-3x+12)-12=10-12$ $-3x=-2$ $-3x\div-3=-2\div-3$ $x=\frac{2}{3}$ The error in the proposed solution was that when the solver distributed $-3$, they forgot that $x-4=x+(-4)$. Since a negative number multiplied by a negative number is a positive number, the correct expression after distribution is not $-3x-12$, but $-3x+12$. Solve the equation accordingly to get the correct solution.